type 2 age based ratio & proportion problems Practice Questions Answers Test with Solutions & More Shortcuts
ratio & proportion PRACTICE TEST [9 - EXERCISES]
type 1 basic concepts of ratio & proportion
type 2 age based ratio & proportion problems
type 3 addition subtraction product on ratio & proportion
type 4 income & expenditure based ratio & proportion problems
type 5 shares & partnership based ratio & proportion problems
type 6 fractions based ratio & proportion problems
type 7 finding sum difference product based ratio & proportion problems
type 8 alligation & mixtures based ratio & proportion problems
type 9 coins & rupees based ratio & proportion problems
Question : 1 [SSC CGL Prelim 2002]
Harsha is 40 years old and Ritu is 60 years old. How many years ago was the ratio of their ages 3:5?
a) 37 years
b) 5 years
c) 20 years
d) 10 years
Answer »Answer: (d)
Let x years ago the ratio of their age was 3 : 5
According to the question
${40 - x}/{60 - x}= 3/5$
200 - 5x = 180 - 3x
2x = 20
x = 10 years
Question : 2 [SSC CGL Prelim 2005]
The ratio of present age of two brothers is 1 : 2 and 5 years back. the ratio was 1 : 3. What will be the ratio of their age after 5 years ?
a) 3 : 5
b) 5 : 6
c) 2 : 3
d) 1 : 4
Answer »Answer: (a)
Let the present age of brothers be x and 2x years.
Then, 5 years ago,
${x - 5}/{2x -5} = 1/3$
3x - 15 = 2x - 5
x = 15 - 5 = 10
Age of elder brother
= 10 × 2 = 20
Required ratio
= ${10 + 5}/{20 + 5} = 15/25$ = 3 : 5
Question : 3 [SSC CGL Prelim 2002]
The ratio of present age of two brothers is 1 : 2 and 5 years back the ratio was 1 : 3. What will be the ratio of their age after 5 years ?
a) 3 : 5
b) 5 : 6
c) 2 : 3
d) 1 : 4
Answer »Answer: (a)
Let the present age of two brothers be x and 2x years.
Now, ${x - 5}/{2x - 5} =1/3$
3x - 15 = 2x - 5
3x - 2x = 15 - 5
x= 10
Their present age
= 10 and 20 years
After 5 years their required ratio
= $15/25 = 3/5$ = 3 : 5
Question : 4 [SSC CGL Tier-I 2014]
The average age of boys in the class is twice the number of girls in the class. The ratio of boys and girls in the class of 50 is 4 : 1. The total of the ages (in years) of the boys in the class is
a) 800
b) 400
c) 2500
d) 2000
Answer »Answer: (a)
Boys in class = $4/5 × 50$ = 40
Girls = $1/5 × 50$ = 10
Average age of boys
= 10 × 2 = 20 years
Total age of boys
= 20 × 40 = 800 years
Question : 5 [SSC CHSL 2010]
The ratio of the age of a father to that of his son is 5: 2. If the product of their ages in years is 1000, then the father's age (in years) after 10 years will be :
a) 80
b) 100
c) 60
d) 50
Answer »Answer: (c)
Let father’s age be 5x years.
Son’s age = 2x years
5x × 2x = 1000
$x^2$ = 100 ⇒ x = 10
Father’s age after 10 years
= 5x + 10
= 5 × 10 + 10 = 60 years
IMPORTANT quantitative aptitude EXERCISES
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199+ Ratio Proportion Basic Concepts MCQ Questions Answers »
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Top 199+ Ratio Proportion Age Based MCQ Questions Answers »
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159+ Ratios Proportions Addition Subtraction product MCQ »
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199+ Ratio Proportion Income, Expenditure Problems MCQS »
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199+ Partnership Aptitude (Ratio) MCQ Questions Answers »
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259+ Ratio and Proportion (fractions) Aptitude MCQ Quiz »
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199+ Ratio and Proportion Aptitude Questions Answers MCQ »
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299+ Alligation and Mixture Problems Aptitude MCQ Quiz »
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249+ Ratio and Proportion Coins Based Questions Answers »
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